Users With Purchase Events
An easy SQL interview practice problem on DataDriven. Write the query and run it against a real database, with instant feedback.
- Domain
- SQL
- Difficulty
- easy
- Seniority
- L3
- Asked in
- Meta
Problem
Return the IDs of every user who has triggered at least one purchase event, listed from the lowest ID to the highest.
At least one purchase. That changes everything.
Tables
event_data
Columns: event_id INTEGER, event_type TEXT, user_id INTEGER, event_timestamp TEXT, payload TEXT, tags TEXT, properties TEXT
| event_id | event_type | user_id | event_timestamp | payload | tags | properties |
|---|---|---|---|---|---|---|
| 3059 | button_click | 100 | 2026-02-02 01:07:00 | {"button_id": "cancel", "element_class": "btn-primary", "position": {"x": 13, "y": 7}} | ["desktop", "web", "returning"] | {"os": "Edge", "language": "US", "screen_size": "en", "utm_source": "mobile"} |
| 3118 | purchase | 197 | 2026-03-03 02:14:00 | {"amount": 56.93, "currency": "GBP", "items": [{"sku": "SKU1002", "qty": 3}]} | ["ios", "premium", "new_user", "organic"] | {"country": "Windows", "device_type": "FR", "referrer": "fr", "utm_medium": "1920x1080", "browser": "twitter"} |
| 3177 | signup | 294 | 2026-04-04 03:21:00 | {"signup_method": "apple", "referral_code": "REF3X", "accepted_terms": true} | ["android", "free", "campaign_a", "referral", "experiment_v1"] | {"language": "iOS", "screen_size": "es", "utm_source": "desktop", "session_id": "bing", "os": "organic"} |
| 3236 | login | 391 | 2026-05-05 04:28:00 | {"login_method": "password", "remember_me": true, "mfa_used": false} | ["web", "returning"] | {"device_type": "JP", "referrer": "ja", "utm_medium": "1440x900"} |
| 3295 | logout | 488 | 2026-06-06 05:35:00 | {"action": "logout", "value": 50} | ["premium", "new_user", "organic"] | {"screen_size": "de", "utm_source": "tablet", "session_id": "amazon", "os": "Chrome"} |
| 3354 | search | 585 | 2026-07-07 06:42:00 | {"query": "phone", "results_count": 102, "filters": {"category": "electronics"}} | ["free", "campaign_a", "referral", "experiment_v1"] | {"referrer": "mobile", "utm_medium": "375x812", "browser": "email", "country": "Edge", "device_type": "US"} |
| 3413 | add_to_cart | NULL | 2026-08-08 07:49:00 | {"product_id": 1007, "quantity": 2, "price": 58.49, "variant": "medium"} | ["returning", "campaign_b", "featured", "experiment_v2", "ios"] | {"utm_source": "fr", "session_id": "twitter", "os": "Safari", "language": "Windows", "screen_size": "FR"} |
| 3472 | open | 779 | 2026-09-09 08:56:00 | {"action": "open", "value": 80} | ["new_user", "organic"] | {"utm_medium": "bing", "browser": "organic", "country": "iOS"} |
| 3531 | crash | 876 | 2026-01-10 09:03:00 | {"action": "crash", "value": 90} | ["campaign_a", "referral", "experiment_v1"] | {"session_id": "direct", "os": "Firefox", "language": "macOS", "screen_size": "JP"} |
| 3590 | error | 973 | 2026-02-11 10:10:00 | {"action": "error", "value": 100} | ["campaign_b", "featured", "experiment_v2", "ios"] | {"browser": "Chrome", "country": "Android", "device_type": "DE", "referrer": "de", "utm_medium": "tablet"} |
users
Columns: user_id INTEGER, username TEXT, email TEXT, signup_date TEXT, account_status TEXT, age_bucket TEXT
| user_id | username | signup_date | account_status | age_bucket | |
|---|---|---|---|---|---|
| 100 | alice | alice@example.com | 2025-02-02 | inactive | 25-34 |
| 197 | aaron42 | aaron42@example.com | 2026-03-03 | suspended | 35-44 |
| 294 | amelia | amelia@example.com | 2024-04-04 | pending_verification | 45-54 |
| 391 | arjun | arjun@example.com | 2025-05-05 | active | 55-64 |
| 488 | ava99 | ava99@example.com | 2026-06-06 | inactive | 65+ |
| 585 | andrew_k | andrew_k@example.com | 2024-07-07 | suspended | NULL |
| 682 | anika | anika@example.com | 2025-08-08 16:34:00 | pending_verification | 18-24 |
| 779 | aiden | aiden@example.com | 2026-09-09 14:53:00 | active | 25-34 |
| 876 | aria_b | aria_b@example.com | 2024-10-10 | inactive | 35-44 |
| 973 | brian | brian@example.com | 2025-11-11 | suspended | 45-54 |
Expected output
| user_id |
|---|
| 197 |
| 1555 |
| 2913 |
| 4271 |
| 5629 |
Worked solution and explanation
Why this problem exists in real interviews
This tests filtering by event type and deduplicating user IDs. Interviewers check whether you can extract a unique set of entities matching a condition and sort them deterministically.
Break down the requirements
Step 1: Filter to purchase events
WHERE event_type = 'purchase' restricts the 200M row table to purchase events only.
Step 2: Return distinct user IDs ordered
SELECT DISTINCT user_id ORDER BY user_id produces a deduplicated, sorted list.
The solution
SELECT DISTINCT user_id
FROM event_data
WHERE event_type = 'purchase'
ORDER BY user_idCommon follow-up questions
- How would you also return the count of purchases per user? (Replace DISTINCT with GROUP BY `user_id` and add COUNT(*).)
- What if `event_type` had mixed casing ('Purchase', 'PURCHASE')? (Use LOWER(`event_type`) = 'purchase' for case-insensitive matching.)
- How would you find users who had both purchase and view events? (Intersect two filtered DISTINCT sets, or use GROUP BY with HAVING.)